Study with Quizlet and memorize flashcards containing terms like Three forces, F 1 = 20.0 N, F 2 = 40.0 N, and F 3 = 10.0 N act on an object with a mass of2.00 kg which can move along a frictionless inclined plane as shown in the figure. The questions refer to the instant when the object has moved through a distance of 0.600 m along the surface of the inclined plane in the upward direction.
Mass of man = 70 kg . Weight carried = 10 kg . Height above ground h = 100 m . Work done =??? Total mass at top of tower = 70 + 10 . M = 80 kg . For a body of mass m to raise to height h above earth, Work done = potential energy stored = M × g × h . Let g = 10 ms-2 . So, work done will be = 80×10×100 = 80,000 J = 80 KJ
Question 2. Determine the work done by gravity if a box of 100 kg is thrown from a height of 23 m. Solution: Given: m = 100 kg, h = 23 m. Work done by gravity = mgh = 100 × 9.8 × 23 J. W g = 22540 J. Question 3. Determine the work done by gravity while a satellite goes around the planet in an orbit with a radius of 100000 km. Solution:
Calculate the work done by the force that changes the velocity of a moving body from 5 ms =$\frac{1}{2}\times 20\times (5^2-2^2)$ =10×(25−4)=10×21 =210 J. 13. An object having 10 kg weight is moved from point A to point B on the table. How much work is done to stop a car of weight 1500 kg moving with a velocity 60 km/h? Ans: Given
Work Calculator How could this calculator be better? Soup Calculator Use This calculator will find the missing variable in the physics equation for Work, when two of the variables are known. Work Equation for these Calculations W = F s Where: W = Work F = Force s = displacement
A weightlifter lifts a weight of mass 25.0 kg through a distance of 0.610 m, then lowers it gently. He does this 25 times. Calculate the net work done by the force of friction due to the rope rubbing ; A person lifts a 4.3 kg centimeter block a vertical distance of 1.10 m and then carries the block horizontally a distance of 10.0 m. The net work is the sum of the work by nonconservative forces plus the work by conservative forces. That is, W net = W nc + W c, 7.55. so that. W nc + W c = Δ KE, 7.56. where W nc is the total work done by all nonconservative forces and W c is the total work done by all conservative forces.
1 kg = 2.2 lbs. Write this in the form of an equation to solve for kilograms: weight in kg = weight in lb x (1 kg / 2.2 lb) The pounds cancel out, leaving kilograms. In essence this means all you have to do to get a kilogram weight in pounds is divide by 2.2: x kg = 176 lbs x 1 kg/2.2 lbs. x kg = 80 kg.
I need help solving this! The work, W (in joules), done when lifting an object varies jointly with the product of the mass, m (in kilograms), of the object and the height, h (in meters), that the object is lifted. The work done when a 120-kilogram object is lifted 1.8 meters above the ground is 2116.8 joules. How much work is done when lifting
An 78.9 kg person carries a 23 N package up a flight of stairs.The vertical height of the stairs is 23.8 meters.How much work is done? What is the work done, if a weight of 25 kilograms is lifted through a vertical height of 2 meters from the ground and it is raised to same place by pushing up an inclined plane making an angle of 30
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Example Problems. Here are a few example problems: (1.a) Consider a constant force of two newtons (F = 2 N) acting on a box of mass three kilograms (M = 3 kg). Calculate the work done on the box if the box is displaced 5 meters. (1.b) Since the box is displaced 5 meters and the force is 2 N, we multiply the two quantities together. (a) Calculate the work done by the weight lifter on the barbell (b) Calculate the work done by the gravitational force. (a) Work=Weight X Distance=(50 kg)(9.81m/sec 2)(0.5 m)= 0.2 kJ to one significant figure. (b) -0.2 kJ if gravitational force is something that can do work. A weightlifter lifts a weight of mass 25.0 kg through a distance of 0.610 m, then lowers it gently. He does this 25 times. Calculate the net work done by the force of friction due to the rope rubbing ; At the gym, a woman lifts 40 kilograms of weights on the leg press machine. A 50 k g man with 20 k g load on his head climbs up 20 steps of 0.25 m height each. The minimum work done by the man on the block during climbing is The minimum work done by the man on the block during climbing is
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